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$ \lim\frac{\sin x-\cos x\sin x}{x^{2}}=\lim\frac{\sin x (1-\cos x)}{x^{2}}=\lim\frac{\sin x}{x}\frac{2\sin^{2}\frac{x}{2}}{x}=\lim\frac{\sin x}{x}\frac{\sin\frac{x}{2}}{\frac{x}{2}}\sin\frac{x}{2}= 1\cdot 1\cdot 0 = 0 $

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