Community

Looking for a challenging geometry text? Preparing for MATHCOUNTS or the AMC exams? Check out Art of Problem Solving's Introduction to Geometry by Richard Rusczyk.
Login Register Memberlist Search AoPS Blogs Contests Galleries Forum Index
The time now is Sun Nov 22, 2009 4:04 pm
All times are UTC - 8
View posts since last visit
View unanswered posts
Kronecker theorem
Moderators: High School Olympiad Moderators, Arne, darij grinberg, harazi, mathmanman, Megus, N.T.TUAN, orl, pbornsztein
Post new topic   Reply to topic View previous topicView next topic
4 Posts • Page 1 of 1
Author Message
Allnames
Yang-Mills Theory
Yang-Mills Theory


Offline
Joined: 15 Jun 2008
Posts: 904
Location: Nghe An province,Vietnam
Viet Nam

To rate posts you must be logged in
#1
Kronecker theorem
require proof and appilactions

1)Prove that the sequence \{na_n\} for all n\ge 1 is dense in [0;1] if a is an irrational humber .
2) Please give me some applications

PostPosted: Sun Jun 07, 2009 7:27 pm  Back to top 
  ProfilePM
MellowMelon
Birch & Swinnerton Dyer
Birch & Swinnerton Dyer


Offline
Joined: 14 Apr 2007
Posts: 2595
Location: Harvey Mudd / Richmond, VA
United States

To rate posts you must be logged in
#2
1) Suffices to show that we can find an n for which 0 < \{ na \} is arbitrarily small, because we get all multiples of it. First, we show given a_n there is an n such that \{na\} < \{a\}/2. Take the first m for which \{ma\} < \{(m-1)a\} (so we had a "carry"). Then \{ma\} < \{a\}. If \{ma\} < \{a\}/2 we're done with n = m. Otherwise as long as \{(1+k(m-1))a\} is positive, \{(1+(k-1)(m-1))a\} - \{(1+k(m-1))a\} = \{a\} - \{ma\} < \{a\}/2. Take the maximum k such that \{(1+k(m-1))a\} is positive, then that means \{(1+k(m-1))a\} < \{a\} - \{ma\} and n = 1+k(m-1) works. Now just replace a with na and repeat ad infinitum.

2) One of many: If a is relatively prime to 10 and d_1d_2 \ldots d_k is a sequence of digits, there are infinitely many powers of a that begin with d_1d_2 \ldots d_k.
_________________
Palmer Mebane
Math blog
Puzzle blog: mellowmelon.wordpress.com

PostPosted: Sun Jun 07, 2009 8:14 pm  Back to top 
  ProfilePMWWWBlog
Mashimaru
Riemann Hypothesis
Riemann Hypothesis


Offline
Joined: 11 Aug 2007
Posts: 284
Location: Highschool for the gifted - National University of HCM city
Viet Nam

To rate posts you must be logged in
#3
MellowMelon wrote:

2) One of many: If a is relatively prime to 10 and d_1d_2 \ldots d_k is a sequence of digits, there are infinitely many powers of a that begin with d_1d_2 \ldots d_k.


How could you prove that? Question

PostPosted: Wed Jul 29, 2009 9:37 am  Back to top 
  ProfilePMYM
tenniskidperson3
Riemann Hypothesis
Riemann Hypothesis

Offline
Joined: 01 Aug 2007
Posts: 284
Location: location, location. That's what I look for in real estate.
United States

To rate posts you must be logged in
#4
Apply the theorem to \log a. Wink
_________________
The tenniskidperson3 effect: The less someone knows someone else, and the younger the someone else is, the higher the first person's voice is.

PostPosted: Wed Jul 29, 2009 2:13 pm  Back to top 
  ProfilePM
Display posts from previous:   Sort by:   
4 Posts • Page 1 of 1
Post new topic   Reply to topic View previous topicView next topic
Jump to:  

You cannot post new topics in this forum
You cannot reply to topics in this forum
You cannot edit your posts in this forum
You cannot delete your posts in this forum
You cannot vote in polls in this forum
You cannot attach files in this forum
You can download files in this forum
You cannot post calendar events in this forum


© Copyright 2008 AoPS Incorporated. All Rights Reserved. • FoundationPrivacyContact Us