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solvable by SOS?
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dyd
Hodge Conjecture
Hodge Conjecture


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#1
solvable by SOS?

For positive reals x,y,z and reals 0<a\leq b\leq c,
b\left( \left( x+y+z\right) ^{2}-4zx\right) \left( c-a\right) ^{2}-4xyc\left( b-a\right) ^{2}-4yza\left( c-b\right) ^{2}\geq ...
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PostPosted: Sun Nov 01, 2009 10:54 am  Back to top 
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dyd
Hodge Conjecture
Hodge Conjecture


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#2
No reply? Sad
I'm learning how to use SOS but none of those 5 criteria is fulfilled. Am I missing something? Or maybe there's a counterexample?
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PostPosted: Wed Nov 04, 2009 6:48 am  Back to top 
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can_hang2007
Navier-Stokes Equations
Navier-Stokes Equations


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#3
Re: solvable by SOS?

dyd wrote:
For positive reals x,y,z and reals 0 < a\leq b\leq c,
b[\left( x + y + z\right) ^{2} - 4zx] \left( c - a\right) ^{2} - 4xyc\left( b - a\right) ^{2} - 4yza\left( c - b\right) ^{2}\...

I will help you. Since c \ge b \ge a>0, we have
b(c-a)^2 -c(a-b)^2-a(b-c)^2 =(c+a)(c-b)(b-a) \ge 0.
Also, it is clear that (x+y+z)^2 -4zx >0,
so we get
b(c-a)^2[(x+y+z)^2-4zx] \ge [a(b-c)^2+c(a-b)^2][(x+y+z)^2-4zx],
and hence, it suffices to show that
a(b-c)^2[(x+y+z)^2-4zx-4yz]+c(a-b)^2[(x+y+z)^2-4zx-4xy] \ge 0,
or
a(b-c)^2(x+y-z)^2 +c(a-b)^2(y+z-x)^2 \ge 0.
Of course, this is true.
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PostPosted: Wed Nov 04, 2009 5:06 pm  Back to top 
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dyd
Hodge Conjecture
Hodge Conjecture


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#4
Thanks!! Your proof makes me think twice before SOS-ing blindly without inspecting the condition of variables Blush
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PostPosted: Thu Nov 05, 2009 2:26 am  Back to top 
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