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Mandelbrot 2009-2010
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pinkmuskrat
Yang-Mills Theory
Yang-Mills Theory


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#1
Mandelbrot 2009-2010
discussion and results

This year's Mandelbrot Competition has gotten under way. Good Luck everyone! Also remember not to discuss rounds until the testing window is over. Smile

mandelbrot.org/
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Star Wars !MATH=AOPS!
Mandelbrot Round 1 UNMPNM Round 1 Mandelbrot Round 2
....YaY #1 aLcUmUs...YaY 1337 gAmEs In FtW...

PostPosted: Wed Nov 04, 2009 5:52 pm  Back to top 
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athunder
Riemann Hypothesis
Riemann Hypothesis


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#2
I believe the last day allowed to take it is November 8th? I geuss we can discuss scores and what not on November 9th.
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MY GOALS: DONT FAIL. 17/50 MMPC II, 25/25 AMC 8, 25/25 MOEMS, 70/80 COMC, Make Nats, 150 AMC 10, 7 AIME Mandelbrot R1=10/14

PostPosted: Thu Nov 05, 2009 4:00 am  Back to top 
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varunrocks
Riemann Hypothesis
Riemann Hypothesis

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#3
can we now discuss the solutions or are people still taking the test.

PostPosted: Mon Nov 09, 2009 4:47 pm  Back to top 
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athunder
Riemann Hypothesis
Riemann Hypothesis


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#4
i dont think so...i have heard something about a "2 week period" so..maybe another week.
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MY GOALS: DONT FAIL. 17/50 MMPC II, 25/25 AMC 8, 25/25 MOEMS, 70/80 COMC, Make Nats, 150 AMC 10, 7 AIME Mandelbrot R1=10/14

PostPosted: Mon Nov 09, 2009 5:08 pm  Back to top 
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darkdieuguerre
Riemann Hypothesis
Riemann Hypothesis

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#5
Quote:
"Students should refrain from discussing the contest problems until Monday following the end of the official testing week."


Well, the testing week ended on Sunday. Therefore, we wait until the Monday after, which is next Monday, November 16th? It would be nice to have an explicit notification on when we can discuss problems, because there is ambiguity, since most of the testing week was last week.
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10^{12} pins make a terrapin.

PostPosted: Mon Nov 09, 2009 5:18 pm  Back to top 
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JBL
Birch & Swinnerton Dyer
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#6
Why don't you send an e-mail to Sam Vandervelde and ask for clarification? Rolling Eyes
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Joel
Hi Deeps! <3

PostPosted: Mon Nov 09, 2009 5:36 pm  Back to top 
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pinkmuskrat
Yang-Mills Theory
Yang-Mills Theory


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#7
darkdieuguerre wrote:
Quote:
"Students should refrain from discussing the contest problems until Monday following the end of the official testing week."


Well, the testing week ended on Sunday. Therefore, we wait until the Monday after, which is next Monday, November 16th? It would be nice to have an explicit notification on when we can discuss problems, because there is ambiguity, since most of the testing week was last week.


I'm pretty sure the "Monday" being referred to is November 9th. Also, results are posted on the website tomorrow.
_________________
Star Wars !MATH=AOPS!
Mandelbrot Round 1 UNMPNM Round 1 Mandelbrot Round 2
....YaY #1 aLcUmUs...YaY 1337 gAmEs In FtW...

PostPosted: Mon Nov 09, 2009 5:48 pm  Back to top 
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xpmath
Birch & Swinnerton Dyer
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#8
Results are up now, you know...

I didn't take round 1, so this is the fourth year in a row I won't be taking all the Mandelbrot rounds.
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Udonis the friendly whale.

PostPosted: Mon Nov 09, 2009 5:51 pm  Back to top 
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not_trig
Navier-Stokes Equations
Navier-Stokes Equations


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#9
uhh those definitely aren't all the results... lots of schools are missing. (No Enloe!)
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RSI '09. Goals: 35 USAMO, IMO, ILO.

PostPosted: Mon Nov 09, 2009 5:59 pm  Back to top 
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pinkmuskrat
Yang-Mills Theory
Yang-Mills Theory


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#10
Mandelbrot posts the results at the stated time (or earlier i guess?!). Those are the results. However, not all the schools have submitted their results yet, and the scoreboard will be later updated accordingly.
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Star Wars !MATH=AOPS!
Mandelbrot Round 1 UNMPNM Round 1 Mandelbrot Round 2
....YaY #1 aLcUmUs...YaY 1337 gAmEs In FtW...

PostPosted: Mon Nov 09, 2009 6:56 pm  Back to top 
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BOGTRO
Birch & Swinnerton Dyer
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#11
Sorry, but where are the results?
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My own chess quotes:
~Chess is not about winning... until you lose~
~The best time to search for alternatives is when you calculate that there are none~

PostPosted: Tue Nov 10, 2009 9:09 am  Back to top 
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pinkmuskrat
Yang-Mills Theory
Yang-Mills Theory


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#12
Go to mandelbrot.org/ and then look on the left side of the site. Under the heading of "Scorecenter", click "Results". There is then a link to national level results, and you can click on the map for regional results.
_________________
Star Wars !MATH=AOPS!
Mandelbrot Round 1 UNMPNM Round 1 Mandelbrot Round 2
....YaY #1 aLcUmUs...YaY 1337 gAmEs In FtW...

PostPosted: Tue Nov 10, 2009 11:48 am  Back to top 
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Differ
Riemann Hypothesis
Riemann Hypothesis


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#13
So how do you solve #7 in a reasonable timeframe?

PostPosted: Thu Nov 12, 2009 2:29 pm  Back to top 
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pinkmuskrat
Yang-Mills Theory
Yang-Mills Theory


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#14
Doesn't seem like there's a solution yet.

The largest discussion on AoPS so far:
http://www.artofproblemsolving.com/Forum/viewtopic.php?t=311057
_________________
Star Wars !MATH=AOPS!
Mandelbrot Round 1 UNMPNM Round 1 Mandelbrot Round 2
....YaY #1 aLcUmUs...YaY 1337 gAmEs In FtW...

PostPosted: Thu Nov 12, 2009 2:45 pm  Back to top 
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math154
Birch & Swinnerton Dyer
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#15
I came up with a casework method during the competition which seemed nice at first but unfortunately requires some stuff which makes it not appealing.

Solution
Let each row have 1609 squares and each column have 2009 squares. Set up position (a,b) for column a and row b, so they start at (1,1) and end at (1609,2009). Now consider the intersection points of red and green (a,b). The back and forth movement motivates casework on parity.

First we note the following (consider moves as including (1,1) and (a,b)):

  • if b is odd, then red moves (b - 1)1609 + a = 1609b + a - 1609 squares
  • if a is odd, then green moves (a - 1)2009 + b = 2009a + b - 2009 squares
  • if b is even, then red moves (b - 1)1609 + (1610 - a) = 1609b - a + 1 squares
  • if a is even, then green moves (a - 1)2009 + (2010 - b) = 2009a - b + 1 squares.

Now we equate and do ugly stuff. Sad

Case 1: a odd, b odd.
2009a + b - 2009 = 1609b + a - 1609\implies2008a = 400 + 1608b \\
\implies251a = 201b + 50\implies50a\equiv50\pmod{201} \\
\i...
Because a is odd, a = 402n + 1, so b = 502n + 1, for 5 solutions when n = 0,1,2,3,4 (remember 1\le a\le1609 and 1\le b\le2009).

Case 2: a odd, b even.
2009a + b - 2009 = 1609b - a + 1\implies2010a = 1608b + 2010 \\
\implies5a = 4b + 5\implies a\equiv1\pmod4 \\
\implies a = 4n...
Because a is odd, a = 8n + 1 so b = 10n, and there are 200 solutions for when 1\le n\le200.

Case 3: a even, b odd.
2009a - b + 1 = 1609b + a - 1609\implies1610b = 2008a + 1610 \\
\implies805b = 1004a + 805\implies805b\equiv805\pmod{1004} \\...
Because b is odd, b = 2008n + 1 so a = 1610n and there are 0 solutions for this case.

Case 4: a even, b even.
2009a - b + 1 = 1609b - a + 1\implies2010a = 1610b \\
\implies201a = 161b\implies40a\equiv0\pmod{161} \\
\implies a = 161n.
Because a is even, a = 322n and b = 402n for 4 solutions when n = 1,2,3,4.

Thus we have 5 + 200 + 0 + 4 = \boxed{209} solutions in all.


So many places for screwing up...

PostPosted: Thu Nov 12, 2009 3:01 pm  Back to top 
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