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Mathcounts marathon!!!!
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AwesomeToad
Yang-Mills Theory
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#5981
NP
Suppose \frac{7^{47}-7^{46}-7^{45}}{41}=7^{x} what is x?


PostPosted: Thu Nov 05, 2009 9:18 am  Back to top 
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isabella2296
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#5982
We can factor out a 7^{45} from the top to get \frac{7^{45}(49 - 7 - 1)}{41} \implies \frac{7^{45}(41)}{41}. The 41's cancel out, leaving us with 7^{45} = 7^{x}, so x = 45.

New problem:

Andy has 3 identical peppermints and 2 identical candy canes. How many ways can he arrange the 5 candies on a table?
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PostPosted: Thu Nov 05, 2009 9:23 am  Back to top 
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$LaTeX$
Riemann Hypothesis
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#5983
Andy can arrange them \frac{5!}{2!3!}=\boxed{10} ways.

NP: The set \{5, 8, 10, 18, 19, 28, 30, x\} has eight members. The
arithmetic mean of the set's members is 4.5 less than x. What is
the value of x ?
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PostPosted: Thu Nov 05, 2009 2:41 pm  Back to top 
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steve123456
Hodge Conjecture
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#5984
(5 + 8 + 10 + 18 + 19 + 28 + 30 + x)/8=x-4.5. 5 + 8 + 10 + 18 + 19 + 28 + 30 + x =8x-36.x= 8x- 154. 7x=154, so x=22

NP: What value of x satisfies the equation 25^-2 = (5^48/x)/(5^[26/x] * 25^[17/x]) Sorry I can't use Latex.

PostPosted: Thu Nov 05, 2009 10:32 pm  Back to top 
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AwesomeToad
Yang-Mills Theory
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#5985
steve123456 wrote:
(5 + 8 + 10 + 18 + 19 + 28 + 30 + x)/8=x-4.5. 5 + 8 + 10 + 18 + 19 + 28 + 30 + x =8x-36.x= 8x- 154. 7x=154, so x=22

NP: What value of x satisfies the equation 25^-2 = (5^48/x)/(5^[26/x] * 25^[17/x]) Sorry I can't use Latex.


Just put dollar signs around the math:
25^-2 = (5^{48/x})/(5^{26/x} * 25^{17/x})

PostPosted: Fri Nov 06, 2009 9:13 am  Back to top 
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fishythefish
Yang-Mills Theory
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#5986
And add a few braces...and fractions if you want:

25^{-2}=\frac{(5^{\frac{48}{x}})}{(5^{\frac{26}{x}})(25^{\frac{17}{x}})}

5^{-4}=5^{\frac{5}{x}}

-4=\frac{5}{x}

x=-\frac{5}{4}

NP:

In one of those "What color hats are the prisoners wearing?" logic problems, there are 10 (distinguishable) prisoners, and 1 red hat, 2 yellow hats, 3 green hats, and 4 blue hats. How many different orders of hats can there be when the prisoners are lined up in order? (Note: hats of the same color are not distinguishable.)
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PostPosted: Sat Nov 07, 2009 2:38 pm  Back to top 
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Maybach
Navier-Stokes Equations
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#5987
Solution

There must be 10! ways to arrange the prisoners and 10!/2!3!4! combinations or 12,600.

NP
Find the value of 37+41.........+101.

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PostPosted: Sat Nov 07, 2009 2:48 pm  Back to top 
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fishythefish
Yang-Mills Theory
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#5988
Should we assume that you are just adding 4 each time? (There are multiple ways to write/solve this, but for simplicity's sake, I'll start the arithmetic series at a_1=37.)

\displaystyle\sum_{n=1}^{17}(33+4n)

S_{17}=\frac{17(37+101)}{2}=\frac{17(138)}{2}=\frac{2346}{2}=1173

NP: What is the answer to my previous problem if there are 5 black prisoners and 5 white ones? (And those of the same color are not distinguishable.)
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PostPosted: Sat Nov 07, 2009 3:03 pm  Back to top 
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brainomega
Hodge Conjecture
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#5989
solution
There are two variables- the color of the hat and the color of the skin. We just multiply the number of ways the hats can be arranged by the number of ways the prisoners can be arranged.\frac{10!}{4!3!2!}\binom{10}5=\boxed{3175200}

np
Bill drove to his work office at 50mph. Realizing that he forgot his portfolio, he rushed back at 65mph. After getting his portfolio, he drove to work at 70mph. What was his average speed for the drives? Round your answer to the nearest tenth.


PostPosted: Sun Nov 08, 2009 8:14 am  Back to top 
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AndrewTom
Navier-Stokes Equations
Navier-Stokes Equations

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#5990
Solution

If the distance between home and office is x, then the total distance is 3x and the total time is \frac{x}{5} + \frac{x}{65} + \frac{x}{70}. Dividing, we find that the average speed is 60.4 to the nearest tenth.


new problem

On a long journey, a motorist drove at 55 miles per hour for the first 2 hours and then at 70 miles per hour for the remainder of the journey. The average speed was 60 miles per hour. How long did the journey take?


PostPosted: Sun Nov 08, 2009 8:41 am  Back to top 
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goldenboy1.618
Poincare Conjecture
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#5991
Solution
The total time is 2 hours at 55 mph and x hours at 70 mph.
The average speed is 60 mph, so the total distance is 60 (2 + x).
Likewise, the total distance is also 55 (2) + 70x = 110 + 70x.
Setting the two distances equal gives 120 + 60x = 110 + 70x\implies10 = 10x.
Simplifying yields x = 1, so the total time is 2 + 1 = \boxed{3}hours.


NP
How many real numbers satisfy |x - 1| + |2x - 3| = |4x - 7|?

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PostPosted: Sun Nov 08, 2009 3:39 pm  Back to top 
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mathking123
Riemann Hypothesis
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#5992
Sorry to interrupt, but when do Chapter competitions start?

PostPosted: Wed Nov 18, 2009 3:51 pm  Back to top 
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PowerOfPi
Navier-Stokes Equations
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#5993
Sometime in February (depending on Chapter), I believe.
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PostPosted: Wed Nov 18, 2009 4:53 pm  Back to top 
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goldenboy1.618
Poincare Conjecture
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#5994
Guess I'll post a Solution.
The solutions are \frac{11}7 and 3. Thus there exist \boxed{2} solutions.

NP
\Delta\text{ABC} has AB = 15, AC = 20, and BC = 10\sqrt3.
Points X and Y are on AB and AC, respectively, such that BX = 8 and CY = 11. What fraction of the area of \Delta\text{ABC} is inside quadrilateral BXYC? Express as a common fraction.

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PostPosted: Sun Nov 22, 2009 12:53 pm  Back to top 
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mathking123
Riemann Hypothesis
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#5995
I would just like to interject that as the author of this marathon, i'm glad that it has finally reached the 300 page mark.

Keep it up!

PostPosted: Thu Nov 26, 2009 5:55 pm  Back to top 
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pytheagle
Riemann Hypothesis
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#5996
Since no one seems to be able to solve goldenboy1.618's problem (or is unwilling to expend the effort to do so and/or then to type up a solution into this thread), I will post a new problem
When you solve this problem
The sum of two positive integers is 56. The sum of their quotient and the reciprocal of their quotient is 2.9. What is the product of the two integers? (Source: MATHCOUNTS)
, please don't be so lazy as to post goldenboy1.618's problem, once again, as the new problem.
.
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PostPosted: Fri Nov 27, 2009 6:30 pm  Back to top 
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PowerOfPi
Navier-Stokes Equations
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#5997
Solution
Translating into math, we get the following equations:
\begin{eqnarray*} a + b & = & 56 \\
 \\
\frac {a}{b} + \frac {b}{a} & = & 2.9 \end{eqnarray*}
Multiplying the last equation by ab, we find that
b + a = 2.9ab .
But we also know that a + b = 56, so we can substitute:
2.9ab = 56
Finally, we divide by 2.9 to find
ab = \boxed{\frac {560}{29}}.

NP
Alice and Bob play a game involving a circle whose circumference is divided by 12 equally-spaced points. The points are numbered clockwise, from 1 to 12. Both start on point 12. Alice moves clockwise and Bob, counterclockwise. In a turn of the game, Alice moves 5 points clockwise and Bob moves 9 points counterclockwise. The game ends when they stop on the same point. How many turns will this take? (Source: AMC)

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Last edited by PowerOfPi on Sat Nov 28, 2009 12:31 pm; edited 1 time in total 
PostPosted: Fri Nov 27, 2009 6:45 pm  Back to top 
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pytheagle
Riemann Hypothesis
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#5998
Solution


We have the following:

12 \rightarrow 5 \rightarrow 10 \rightarrow 3 \rightarrow 8 \rightarrow 1 \rightarrow 6 : \ \text{Alice}
12 \rightarrow 3 \rightarrow 6 \rightarrow 9 \rightarrow 12 \rightarrow 3 \rightarrow 6 : \ \text{Bob}

Therefore, the answer is \boxed{6}.



New Problem: Select any three-digit multiple of 3. Calculate the sum of the cubes of the digits of that number. This is now your new number. Now calculate the sum of the cubes of the digits of this new number. Continue this procedure of adding the cubes of the digits of the resulting number until you arrive at a number that is equal to the sum of the cubes of its digits. What is this number? (Source: MATHCOUNTS)
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PostPosted: Sat Nov 28, 2009 11:37 am  Back to top 
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the cliu
Riemann Hypothesis
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#5999
answer
153=1^{3} + 5^{3} + 3^{3}


I really don't know if there is any other way besides guess and check.

NP
Heather and Isabelle play a two-person game which is won by the first person to accumulate 10 points. At each turn Heather gains a point with probability of \frac{2}{3} . If she doesn't get a point then Isabelle gets a point. Isabelle is now ahead 9 to 6. What is the probability that Isabelle will win? Express your answer as a common fraction.


PostPosted: Sat Nov 28, 2009 11:55 am  Back to top 
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goldenboy1.618
Poincare Conjecture
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#6000
Solution
The only way Heather can win at this point is if she scores 4 turns in a row. The probability that she scores 4 points now is (\frac{2}{3})^4 = \frac{16}{81}.

Isabelle wins in any other circumstance, so her probability is 1 - \frac{16}{81} = \boxed{\frac{65}{81}}.


NP
Joanna chooses a two digit positive integer. She multiplies the tens digit by 3, and she multiplies the units digit by 4. When Joanna adds these two quantities, the sum is her original number. What is Joanna's integer?

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PostPosted: Sat Nov 28, 2009 12:30 pm  Back to top 
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