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How many are there?
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mathVNpro
Riemann Hypothesis
Riemann Hypothesis

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Location: Le Hong Phong, Ho Chi Minh city, Viet Nam
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#1
How many are there?

In the set of n positive interger numbers S=\{1,2,...,n\}. (a,b,c,d) is 4 numbers which is taken from S. (a,b,c,d) is call good if we have a+b=c+d. How many good (a,b,c,d)?

PostPosted: Sun Nov 08, 2009 2:53 pm  Back to top 
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evoluciona
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#2
Re: How many are there?

Let f(m) = the number of solutions of a+b=m with a,b in S.
Then you're after
\sum_{m=2}^{2n} f(m)^2.

f(m) takes the values 1,2,3,...,n,...,3,2,1 on this sequence of m - might have this wrong Smile

so you want

2\sum_{j=1}^{n-1} j^2 + n^2 = (n-1)n(2n-1)/3 + n^2 = 2n^3/3 + n/3
-evo

PostPosted: Sun Nov 08, 2009 4:42 pm  Back to top 
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mathVNpro
Riemann Hypothesis
Riemann Hypothesis

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Joined: 20 Nov 2008
Posts: 374
Location: Le Hong Phong, Ho Chi Minh city, Viet Nam
Viet Nam

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#3
Re: How many are there?

evoluciona wrote:
Let f(m) = the number of solutions of a+b=m with a,b in S.
Then you're after
\sum_{m = 2}^{2n} f(m)^2.

f(m) takes the values 1,2,3,...,n,...,3,2,1 on this sequence of m - might have this wrong Smile

so you want

2\sum_{j = 1}^{n - 1} j^2 + n^2 = (n - 1)n(2n - 1)/3 + n^2 = 2n^3/3 + n/3
-evo


Can you give a clearer explantion to your proof? It seems interesting! Idea

PostPosted: Sun Nov 08, 2009 4:46 pm  Back to top 
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