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Post Posted: May 02, 2007, 4:54 pm • # 1 


Let a,b,c be nonzero real numbers. Find all ordered pairs (a,b,c) such that

\frac{2(a-b-c)}{a^{2}}=\frac{4b-a-2c}{b^{2}}=\frac{4c-a-2b}{c^{2}}

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Post Posted: May 02, 2007, 4:59 pm • # 2 


Big hint

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Post Posted: May 02, 2007, 6:14 pm • # 3 


If \frac{a}{b}=\frac{c}{d}=\frac{e}{f}, then \frac{a}{b}=\frac{c}{d}=\frac{e}{f}=\frac{a+c+e}{b+d+f}.
 
 
Post Posted: May 02, 2007, 7:02 pm • # 4 


drunner2007 wrote:
Let a,b,c be nonzero real numbers. Find all ordered pairs (a,b,c) such that

\frac{2(a-b-c)}{a^{2}}=\frac{4b-a-2c}{b^{2}}=\frac{4c-a-2b}{c^{2}}


solution based off of the hints
 
 
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