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pytheagle
Riemann Hypothesis
Offline Joined: 02 Jun 2009 Posts: 329 Location: Houston, TX
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Solution
By definition of probability, we have
Since we have two choices for every toss namely heads or tails, we have
.
Let H be heads, T be tails, and _ represent a toss. Then, the desired outcomes are presented as follows:
1) H H H T _ _ _ _ _ _
2) T H H H T _ _ _ _ _
3) _ T H H H T _ _ _ _
4) _ _ T H H H T _ _ _
5) _ _ _ T H H H T _ _
6) _ _ _ _ T H H H T _
7) _ _ _ _ _ T H H H T
Notice that for all seven of the cases, we need to choose either H or T for the remaining six tosses leading to
.
Hence, our answer is
.
New Problem
A student's scores on five mathematics tests were
and
. The student needs an average score of eighty-one to receive a B grade on the report card. What is the lowest score the student can obtain on the one remaining test before report cards and still receive a B grade?
(Source: MATHCOUNTS)
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Posted: Fri Oct 09, 2009 7:38 pm
greenhand
Hodge Conjecture
Offline Joined: 02 Oct 2009 Posts: 52 Location: 37°N,114°30'E
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pytheagle wrote:
Solution
By definition of probability, we have
Since we have two choices for every toss namely heads or tails, we have
.
Let H be heads, T be tails, and _ represent a toss. Then, the desired outcomes are presented as follows:
1) H H H T _ _ _ _ _ _
2) T H H H T _ _ _ _ _
3) _ T H H H T _ _ _ _
4) _ _ T H H H T _ _ _
5) _ _ _ T H H H T _ _
6) _ _ _ _ T H H H T _
7) _ _ _ _ _ T H H H T
Notice that for all seven of the cases, we need to choose either H or T for the remaining six tosses leading to
.
Hence, our answer is
.
New Problem
A student's scores on five mathematics tests were
and
. The student needs an average score of eighty-one to receive a B grade on the report card. What is the lowest score the student can obtain on the one remaining test before report cards and still receive a B grade?
(Source: MATHCOUNTS)
solution
Posted: Sat Oct 10, 2009 5:57 am
garfielddisco123
Poincare Conjecture
Offline Joined: 23 Sep 2009 Posts: 125 Location: Somewhere over the rainbow
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Hi do not look, answer ans solution (83+67+79+92+70+x)/6=81
83+67+79+92+70+x=486
391+x=486
x=95
Posted: Sat Oct 10, 2009 6:30 am
gaussintraining
Riemann Hypothesis
Offline Joined: 23 Aug 2009 Posts: 391
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New Problem
The parallel sides of an isosceles trapezoid have lengths of
units and
units, and the perimeter is
units. What is the area of the trapezoid?
Posted: Sat Oct 10, 2009 7:33 am
AndrewTom
Navier-Stokes Equations
Offline Joined: 13 Dec 2006 Posts: 1649
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Solution
Length of equal sides = (74 - 19 - 29)/2 = 13. Perpendicular height = 12, by Pythagoras.
Area = 12(29+19)/2 = 288.
New problem
Prove that ax^2 + bx + c takes integral values for all values of x if and only if 2a, a+b and c are each integers.
Posted: Sat Oct 10, 2009 10:55 am
pytheagle
Riemann Hypothesis
Offline Joined: 02 Jun 2009 Posts: 329 Location: Houston, TX
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The general term "MATHCOUNTS Level" does not extend to include problems in which proofs are required.
New Problem
How many strings of 3 letters do not include a B?
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Posted: Sat Oct 10, 2009 11:55 am
cgyao15
Navier-Stokes Equations
Offline Joined: 08 Nov 2007 Posts: 1166 Location: STALKER!!! >:(
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go calculate
NP
Find number of ways to spell: cgyao15cyao15 as 1 word.
Posted: Sat Oct 10, 2009 12:17 pm
goldenboy1.618
Poincare Conjecture
Offline Joined: 14 Mar 2009 Posts: 147 Location: USA
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Solution Assuming you meant cgyao15cgyao15, we have 14 letters to be arranged in
permutations. Dividing by
for repetition gives
.
NP If Kelly is 36 years old, then Mark is 29 years old. If Kelly is not 36, then Andrea is not 14. Andrea is indeed 14. Mark is either 29 or 45. How old is Mark? (From a school entrance exam)
_________________
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pi to
i : "Get real!"
Posted: Sat Oct 10, 2009 3:18 pm
Maybach
Navier-Stokes Equations
Offline Joined: 06 Jun 2009 Posts: 1728 Location: NW Indiana
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Solution
Um.....REALLY EASY
This means Kelly is 36 and Mark is 25. (Wow, some school entrance exam
)
NP
In Texas, 10 students on the 2009 Mathcounts State Competition got 46/46. If only 4 people can make the national competition and one of them was already determined, how many ways can the remaining 3 people be selected from the remaining students?
_________________ Goals: Make MC Nats, get 25 on AMC8, get 40/40 on Math League, 120 AMC10
Name Change: maybach to Maybach! :rofl:
Posted: Sat Oct 10, 2009 3:39 pm
the cliu
Poincare Conjecture
Offline Joined: 11 Jun 2009 Posts: 248 Location: The lower part of the MITTEN
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solution Since one of them was already determined, there are 9 students left to distribute to 3 spots on the National Math Counts team. Since order doesn't really matter, our answer is
new problem The probability that
cliu will eat Chinese food for dinner is
. The probability that
cliu will eat Chinese food for lunch is
. What is the probability that
cliu will not eat Chinese food for lunch or dinner?
Posted: Sat Oct 10, 2009 7:05 pm
Maybach
Navier-Stokes Equations
Offline Joined: 06 Jun 2009 Posts: 1728 Location: NW Indiana
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Solution
Complementary counting:
1/9 * 11/13 = 11/117
NP
The probability that Maybach will have Chinese food for lunch is
. The probability Maybach will have Chinese food for dinner is
. What's the probability Maybach will have Chinese food for both lunch and dinner?(I always feel sick to my stomach after eating spicy food)
_________________ Goals: Make MC Nats, get 25 on AMC8, get 40/40 on Math League, 120 AMC10
Name Change: maybach to Maybach! :rofl:
Posted: Sun Oct 11, 2009 5:25 am
greenhand
Hodge Conjecture
Offline Joined: 02 Oct 2009 Posts: 52 Location: 37°N,114°30'E
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solution
new problem
Find the focus and the directrix of the parabola
Posted: Sun Oct 11, 2009 5:32 am
AndrewTom
Navier-Stokes Equations
Offline Joined: 13 Dec 2006 Posts: 1649
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Mathycounts marathon!!!!
This seems rather difficult for this level.
Solution
Comparing with
, which has its focus at
and directrix
, by completing the square to get
in the form
, I get the focus at
and the directrix as
New problem
Make
with five
s.
Posted: Sun Oct 11, 2009 6:34 am
Thunder365
Yang-Mills Theory
Offline Joined: 27 Feb 2009 Posts: 528 Location: Michigan
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lol
Solution 100=111-11
NP Carla is writing all the numbers from 0 to 99999 inclusive on a piece of paper. How many times does the digit "1" appear?
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I'm not dumb. I just have a command of thoroughly useless information.
Goals: AMC8:25| AMC10:138+|AIME:5+| Mandelbrot:Leaderboard| Mathcounts:Make Nats| MMPC part 1:28+, MMPC part 2:16+, top 100=>Michigan ARML B team| USAMTS:Bronze| Make CMO
Posted: Sun Oct 11, 2009 7:02 am
cgyao15
Navier-Stokes Equations
Offline Joined: 08 Nov 2007 Posts: 1166 Location: STALKER!!! >:(
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@goldenboy i didn't make a typo, cyao15 is a player too you know
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Posted: Sun Oct 11, 2009 3:47 pm
goldenboy1.618
Poincare Conjecture
Offline Joined: 14 Mar 2009 Posts: 147 Location: USA
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@cgyao15 Sorry for the confusion.
Solution She writes 100,000 total numbers. This means she writes 1 in the units place 10,000 times, in the tens place 10,000 times, and so on for each place value, giving her a total number of
ones.
NP What is the degree measure of the smaller angle formed by a clock's hands at 8:20?
_________________
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pi to
i : "Get real!"
Posted: Wed Oct 14, 2009 4:35 am
AwesomeToad
Yang-Mills Theory
Offline Joined: 25 Apr 2009 Posts: 813 Location: West Lafayette, IN (Rating: 1337)
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Solution The minute hand is
degrees past the
and the hour hand is
so the smaller angle formed is
degrees
New Problem Find all real solutions of
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Mock AMC! Participation encouranged and appreciated!
Posted: Wed Oct 14, 2009 8:21 am
AndrewTom
Navier-Stokes Equations
Offline Joined: 13 Dec 2006 Posts: 1649
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Solution
Sketching the graph,
or
.
Alternatively, square both sides and factorise to get
, giving the real roots
.
NP
Solve
.
Posted: Wed Oct 14, 2009 10:19 am
gauss1181
Birch & Swinnerton Dyer
Offline Joined: 08 Sep 2007 Posts: 2608 Location: IMSA
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The absolute values must be both 0. But that's not possible.
So there are in this equation.
NP:
Find the radius of the incircle of a triangle with side lengths 7, 24, and 25.
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Latest Problems Typed: 1979 ISL number theory problem
Posted: Wed Oct 14, 2009 10:37 am
Thunder365
Yang-Mills Theory
Offline Joined: 27 Feb 2009 Posts: 528 Location: Michigan
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Solution:
A=RS
7-24-25 is a right triangle, so A=84. S=(7+24+25)/2=28. 84/28=3
NP:
Six students are going to sit in a row for Countdown Round in Mathcounts. Thunder wants to sit next to cliu. Athunder does not want to sit next to Alex. The other two people can sit anywhere. How many ways can these six students be seated?
_________________
I'm not dumb. I just have a command of thoroughly useless information.
Goals: AMC8:25| AMC10:138+|AIME:5+| Mandelbrot:Leaderboard| Mathcounts:Make Nats| MMPC part 1:28+, MMPC part 2:16+, top 100=>Michigan ARML B team| USAMTS:Bronze| Make CMO
Posted: Wed Oct 14, 2009 1:34 pm
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