i found

and

.
suppose we have a solution, and consider it as a quadratic in

. we have its discriminant equals

. it has to be a perfect square so

.
suppose that

and

. so, we have that

.
consider it again as a quadratic in

. we have its discriminant equals

. again we take

and

, so,

.
consider it again as a quadratic in

. its discriminant equals

. take

. we have to find a integer

such that

. for

we have that

.
if we return to previous equations, we find that

, so we find

... analogously we find

. if

we find

. if

we find

, and that's how i found them
