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MOEMS Marathon
Moderators: AIME15, frost13, isabella2296, LadyKn1ght, nebula42, rcv, solafidefarms
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isabella2296
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#1
 MOEMS Marathon

Rules:

1. Keep it MOEMS level.
2. When you answer, give a new problem. You can always make up one, or use Google.

Problem One:

Sally is thinking of a number. The product of the digits is one half of the number. What is the smallest positive, two-digit integer she could be thinking of?
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PostPosted: Mon Jul 28, 2008 3:30 pm  Back to top 
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mz94
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#2
call the tens digit a and the ones digit b. then the numerical value is 10a+b

now we know that ab = \frac{1}{2}(10a + b) so 2ab = 10a + b now we knwo b is even


the smallest number satisfying that is 36


new prob


find the hypontenuse of a triangle with legs 20 and 21
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Last edited by mz94 on Mon Jul 28, 2008 3:43 pm; edited 1 time in total 
PostPosted: Mon Jul 28, 2008 3:37 pm  Back to top 
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isabella2296
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#3
We use the Pythagorean Theorem.

20^2 + 21^2 = 841

\boxed{29}

New Problem:

Similar to the first problem --

Randy wants to find the smallest, positive, two-digit integer which is twice the sum of its digits. What is it?
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PostPosted: Mon Jul 28, 2008 3:40 pm  Back to top 
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mz94
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#4
this is easier. call the 2 digit number (once again) 10a+b. then the sum is a+b
10a+b=2(a+b). simplifying gives us 8a=b. the smallest number is therefore when a=1, b=8


18


new prob:

find the 2 digit number which is 120% the number that is formed when tis digits are reversed
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Oh, and just in case you didn't notice, Angie is my beeeest friend! =)

PostPosted: Mon Jul 28, 2008 3:46 pm  Back to top 
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AIME15
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#5
45
i have no new probbbbbbbbbbbbbbbbbbb

PostPosted: Mon Jul 28, 2008 4:32 pm  Back to top 
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FantasyLover
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#6
wth?? ernie's marathon got locked too??

let the 2 digit number be xy.

xy=\frac{6}{5}yx.

10x+y=\frac{6}{5}(10y+x)=12y+\frac{6}{5}x

\frac{44}{5}x=11y, x=5 y=4

answer : 54

<New Problem>

What is the area of the triangle with side lengths 12, 16, and 20?
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PostPosted: Mon Jul 28, 2008 4:35 pm  Back to top 
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Bachukas
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#7
mz94 wrote:
this is easier. call the 2 digit number (once again) 10a+b. then the sum is a+b
10a+b=2(a+b). simplifying gives us 8a=b. the smallest number is therefore when a=1, b=8


18


new prob:

find the 2 digit number which is 120% the number that is formed when tis digits are reversed

10a+b=1,2(10b+a)
8,8a=11b
4a=5b a divisible by 5 and a<10, so a=5, b=4 Answer: 54

<New problem>
Find x:
x= \frac {1}{1*2}+\frac {1}{3*4}+\frac {1}{5*6}+...+\frac {1}{99*100}

PostPosted: Mon Jul 28, 2008 5:06 pm  Back to top 
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mz94
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#8
Bachukas wrote:


<New problem>
Find x:
x = \frac {1}{1*2} + \frac {1}{3*4} + \frac {1}{5*6} + ... + \frac {1}{99*100}


to attempt to solve this we will investigate the first few terms


\frac {1}{1*2} = \frac {1}{2}
\frac {1}{1*2} + \frac {1}{3*4} = \frac {3}{4}
\frac {1}{1*2} + \frac {1}{3*4} + \frac {1}{5*6} = \frac {5}{6}

well! it would appear

\frac {1}{1*2} + \frac {1}{3*4} + ...\frac {1}{n(n + 1)} = \frac {n}{n + 1}

so since n in this case is 99, our answer is \frac {99}{100}

and fantasy yours is 12*16/2 (its a right triangle), which is 96

new prob

3 Germans, 4 British, and 5 Americans sit in a row of chairs in a meeting. if they insist on sitting as groups, with each nationality being one group, how many seating combinations are there?
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PostPosted: Mon Jul 28, 2008 5:41 pm  Back to top 
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Bachukas
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#9
mz94 wrote:

\frac {1}{1*2} = \frac {1}{2}
\frac {1}{1*2} + \frac {1}{3*4} = \frac {3}{4}
\frac {1}{1*2} + \frac {1}{3*4} + \frac {1}{5*6} = \frac {5}{6}


\frac {1}{1*2} = \frac {1}{2}
\frac {1}{1*2} + \frac {1}{3*4} = \frac {7}{12}
\frac {1}{1*2} + \frac {1}{3*4} + \frac {1}{5*6} = \frac {37}{60}

Your answer is false

PostPosted: Mon Jul 28, 2008 11:10 pm  Back to top 
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isabella2296
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#10
These problems are getting a little too hard. I'll post an easier one, because I'd hate to get this locked.

Mr. Holmes buys a chair for \$60. He tries to sell it for double the price, but when no one would buy it, he reduced that doubled price by 60\%. However, sales tax is 7\%. Including tax, what was the final price of the chair?
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PostPosted: Tue Jul 29, 2008 3:39 am  Back to top 
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ernie
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#11
So, here's what you do.

60 \cdot 2 = 120

But since no one wanted to buy it at that price, we reduce it by 60%.

120 \cdot 0.4 = 48

Add tax.

48 \cdot 1.07 = \boxed{51.36}

Problem 9
If the hypotenuse of a right triangle is 25, then what is the smallest possible leg, if the two legs must be whole-integer lengths?

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PostPosted: Tue Jul 29, 2008 3:56 am  Back to top 
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isabella2296
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#12
Ernie, I believe that problem is too hard. Do you have another?
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PostPosted: Tue Jul 29, 2008 4:03 am  Back to top 
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FantasyLover
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#13
meh, ill just solve it and post another problem.

ernie's - 7 and 24

<Problem 10>

Evaluate: (3^4)^\frac{5}{4}
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PostPosted: Tue Jul 29, 2008 4:48 am  Back to top 
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heneieneh
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#14
THe fourth root of 3^4 cancels out to become 3. we then find 3^5 which is 243

PostPosted: Tue Jul 29, 2008 5:38 am  Back to top 
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isabella2296
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#15
In the future, please post a second problem. Also, I suggest reading the rules in the first post.

New Problem:

[Taken from my blog] Compute the following without using a calculator: \frac{8!}{6!2!}.
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PostPosted: Tue Jul 29, 2008 5:44 am  Back to top 
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ernie
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#16
isabella2296 wrote:
In the future, please post a second problem. Also, I suggest reading the rules in the first post.

New Problem:

[Taken from my blog] Compute the following without using a calculator: \frac {8!}{6!2!}.


Very self-explanatory, the answer is \frac{7 \cdot 8}{2} or 28.

Problem 12
Mr. Schnitzelheimer bought a cake, for 9.27 dollars, including tax. How much was the tax if the tax was 3%?

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PostPosted: Tue Jul 29, 2008 5:48 am  Back to top 
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isabella2296
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#17
Let x be the amount of money the tie costs, without tax.

1.03x = 9.27

x = 9

Thus, the tie costs \$9.

If you take my age, double it, and add 1, you'll get the 9th prime number. How old am I?
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PostPosted: Tue Jul 29, 2008 5:52 am  Back to top 
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ernie
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#18
isabella2296 wrote:
Let x be the amount of money the tie costs, without tax.

1.03x = 9.27

x = 9

Thus, the tie costs \$9.

If you take my age, double it, and add 1, you'll get the 9th prime number. How old am I?


Kinda ruining it... but you told me your 11, so I guess thats the answer.

Problem 14: I eat out at the Deluxe Burger Plaza, and I buy a burger. I use my credit card, which gives me 2% returns (including tax), after the credit card charges me 10% for their fees. I pay 20 dollars for the burger. How much money do I get from rewards, if tax is 5% and is included?
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PostPosted: Tue Jul 29, 2008 5:59 am  Back to top 
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isabella2296
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#19
Ernie, please post a solution. Mr. Green
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PostPosted: Tue Jul 29, 2008 6:25 am  Back to top 
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#20
Problems are still too hard. You would never see a fractional exponent problem - a largely Algebra 2 topic - on a test geared for 4th through 8th graders.

PostPosted: Tue Jul 29, 2008 8:15 am  Back to top 
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