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remy1140
Poincare Conjecture
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Red MOP cutoff
I understand that this changes every year, but what is the usual minimum USAMO score necessary to make Red MOP? Or, since USAMO is really focusing on #1 and 4 from now on, around what score would be the cutoff in those two problems?
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Posted: Sat Oct 03, 2009 7:53 pm
andersonw
Yang-Mills Theory
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Usually, the cutoff is around 9-10 (1 problem fully solved, partial credit on 1-2 other problems), but now that they're only going to use 2 problems, it will probably be 7-8 (or even lower), because some people taking USAMO may solve, say, problem 2 and not problem 1, but it wouldn't count toward red MOP. Also, if you solve 1 problem, you can only get additional partial credit on 1 other problem, unlike when you could get partial credit on 5 other problems.
For example, if only 1 and 4 were counted toward red MOP on last year's USAMO, the cutoff score would have most likely been 7 or 6 instead of 8, because lots of people got 2 free points on problem 2, which wouldn't count under the new system.
(unfortunately, I got a 7 last year )
Posted: Sun Oct 04, 2009 6:47 am
Ihatepie
Navier-Stokes Equations
Offline Joined: 25 Oct 2006 Posts: 1881 Location: Southwest, CT
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andersonw wrote:
Usually, the cutoff is around 9-10 (1 problem fully solved, partial credit on 1-2 other problems), but now that they're only going to use 2 problems, it will probably be 7-8 (or even lower), because some people taking USAMO may solve, say, problem 2 and not problem 1, but it wouldn't count toward red MOP. Also, if you solve 1 problem, you can only get additional partial credit on 1 other problem, unlike when you could get partial credit on 5 other problems.
For example, if only 1 and 4 were counted toward red MOP on last year's USAMO, the cutoff score would have most likely been 7 or 6 instead of 8, because lots of people got 2 free points on problem 2, which wouldn't count under the new system.
(unfortunately, I got a 7 last year )
You sure? I was under the impression that all of the USAMO problems counted for red MOP.
The only difference was that the USAJMO participants could only use the last 3 and 6 questions.
_________________ 2010 Goals: ARML-7 AMC10- 144 AMC12- 126 AIME- 8 USAJMO-14?
Posted: Sun Oct 04, 2009 7:39 am
modularmarc101
Navier-Stokes Equations
Online Joined: 04 May 2008 Posts: 1178 Location: Puerto Rico
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Really? Then what's the point of taking the whole test if only 2 problems count? It would be pretty sad to get points on other problems but those 2..
_________________ Goals: 140+ AMC 10 | 7+ AIME | 10+ USAJMO | 65+ USAMTS (Bronze Medal) |
Posted: Sun Oct 04, 2009 7:55 am
Bugi
Birch & Swinnerton Dyer
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To get to Blue MOP, Black MOP?
Posted: Sun Oct 04, 2009 8:06 am
remy1140
Poincare Conjecture
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Also for tiebreaker, in case some 2 people tied on #1 and 4 scores.
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Posted: Sun Oct 04, 2009 8:38 am
not_trig
Navier-Stokes Equations
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Bugi wrote:
To get to Blue MOP, Black MOP?
Unfortunately solving 6 problems on USAJMO doesn't get you into anything but Red.
_________________ RSI '09. Goals: 35 USAMO, IMO, ILO.
Posted: Sun Oct 04, 2009 12:28 pm
Bugi
Birch & Swinnerton Dyer
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So basically, your USAJMO doesn't give you anything? No international competitions, nothing more than red MOP?
Why is it introduced then?
Posted: Sun Oct 04, 2009 12:34 pm
remy1140
Poincare Conjecture
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According to the AMC Director, it is created to give a chance to beginners in olympiad who do not have much experience so that they won't get to intimidated by the difficulty of USAMO. But I don't see how we would really get frightened because of USAMO if we at least tried...
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Posted: Sun Oct 04, 2009 1:09 pm
worthawholebean
Navier-Stokes Equations
Offline Joined: 09 May 2005 Posts: 2162 Location: New Haven, CT
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I know multiple people at my school who are just almost good enough to qualify for USAMO. They are definitely good enough for USAJMO, and would much rather take it than the USAMO, which is very intimidating. Remember, the set of people on AoPS is exactly the set of people who would be motivated by a really difficult contest - for others who are different, it's a good idea to have the intermediate level. AIME to USAMO is a gigantic jump, especially for people unfamiliar with proofs.
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Posted: Sun Oct 04, 2009 1:54 pm
AwesomeToad
Yang-Mills Theory
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This year:
Red MOP: 8+
Blue MOP: 20+
Black MOP: 27+
Posted: Sun Oct 04, 2009 3:32 pm
kyyuanmathcount
Navier-Stokes Equations
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Blue was 18 this year.
To get to red, you should just be comfortable with #1 and #4.
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-Allen Yuan
Posted: Sun Oct 11, 2009 9:07 am
iYOA
Poincare Conjecture
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what if someone gets a 9 on USAMO but solves problem 2 and get partial credit on problem 1?
(this scenario might be possible because the ninth grader could have first solved 2 and not had enough time to do 1 properly)
would they still qualify for red MOP assuming the cutoff is about 7-8?
Posted: Sun Oct 11, 2009 2:49 pm
andersonw
Yang-Mills Theory
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Under the current rules, no.
(I think this is pretty clear based on what was already said in this thread, and it's also not that hard to search "USAJMO" to find more details on it )
Posted: Sun Oct 11, 2009 4:15 pm
Ihatepie
Navier-Stokes Equations
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andersonw wrote:
Under the current rules, no.
(I think this is pretty clear based on what was already said in this thread, and it's also not that hard to search "USAJMO" to find more details on it )
Are you sure? Doesn't it say that if you're in the USAMO you can do as many problems as you want, while the USAJMO is just limited to those two?
_________________ 2010 Goals: ARML-7 AMC10- 144 AMC12- 126 AIME- 8 USAJMO-14?
Posted: Sun Oct 11, 2009 5:41 pm
sup3rcrash3r
Poincare Conjecture
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Then that would be unfair because USAMO would have 6 problems that count toward qualification, while USAJMO would only have 2.
Posted: Sun Oct 25, 2009 9:45 am
MellowMelon
Birch & Swinnerton Dyer
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1. That the entire USAMO score counts for red MOP is a frequently suggested proposal on this forum, frequent enough to (I think) mislead people here. I have not seen AMCDirector say anything about changing their original policy of counting only J3/J6 and 1/4.
2. To the above: It's not necessarily unfair. It is harder to make the USAMO than the USAJMO.
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Math blog
Puzzle blog: mellowmelon.wordpress.com
Posted: Sun Oct 25, 2009 11:08 am
mathwizarddude
Navier-Stokes Equations
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Just wondering what would a sophemore get from taking the USAJMO (since that would only help you get to Red MOP only)?
Posted: Sat Oct 31, 2009 9:44 pm
Mewto55555
Birch & Swinnerton Dyer
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Absolutely nothing, other than possibly the honor of being a USAJMO winner (sort of like MVP of the AAA baseball world series?)
_________________ 2009 MC:2nd written, 3rd cd, masters winner. Not bad.
Now to be cliche and list my goals: Silver USAMTS (Bronze if I forget to turn one in), 10 ARML, 150 AMC 10, 150 AMC 12, 13 AIME, Blue MOP, Top 20 Mandelbrot
Posted: Sun Nov 01, 2009 9:44 am
Ihatepie
Navier-Stokes Equations
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You'd get the experience of solving olympiad questions in an actual test environment, hopefully it would help you do better the next year in the USAMO.
_________________ 2010 Goals: ARML-7 AMC10- 144 AMC12- 126 AIME- 8 USAJMO-14?
Posted: Sun Nov 01, 2009 10:35 am
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