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A simple but nice inequality
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Agr_94_Math
Yang-Mills Theory
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#1
A simple but nice inequality

Given real numbers a,b,c such that \frac {1}{2} \le a,b,c \le 1
Prove that 2\le \sum \frac {a + b}{1 + c} \le 3.

PostPosted: Sun Nov 08, 2009 12:12 am  Back to top 
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Pain rinnegan
Poincare Conjecture
Poincare Conjecture


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#2
Re: A simple but nice inequality

Agr_94_Math wrote:
Given real numbers a,b,c such that \frac {1}{2} \le a,b,c \le 1
Prove that 2\le \sum \frac {a + b}{1 + c} \le 3.


Search for Romania 2006 .

PostPosted: Sun Nov 08, 2009 12:46 am  Back to top 
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aadil
Riemann Hypothesis
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#3
\frac {a + b}{1 + c} < = \frac {2(a + b)}{3}, \frac {b + c}{1 + a} < = \frac {2(b + c)}{3}, \frac {a + c}{1 + b} < =....on adding we get \sum_cyc \frac {a + b}{1 - c} < = \frac {4(a + b + c)}{3} < = 3.
i am unable to prove the left hand side Sad
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Last edited by aadil on Sun Nov 08, 2009 4:27 am; edited 1 time in total 
PostPosted: Sun Nov 08, 2009 2:20 am  Back to top 
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geniusbliss
Riemann Hypothesis
Riemann Hypothesis


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#4
http://www.artofproblemsolving.com/Forum/viewtopic.php?t=84221
also,
aadil wrote:
\frac {a + b}{1 + c} < = \frac {2(a + b)}{3}, \frac {b + c}{1 + a} < = \frac {2(b + c)}{3}, \frac {a + c}{1 + b} < =....on adding we get \sum_cyc \frac {a + b}{1 - c} < = \frac {4(a + b + c)}{3} < = 3.
i am unable to prove the right hand side Sad

am i too dum but how is \frac {4(a + b + c)}{3} < = 3 that is not true is it?wat abt a=b=c=1
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PostPosted: Sun Nov 08, 2009 3:58 am  Back to top 
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