Implicit differentiation

DJIntel

I'm having a problem with solving this implicitly. It says find dy/dx if x=sin(x+y). I got an answer but not sure if it's the correct one.

**Posted:** Sat Sep 17, 2005 6:30 am

leepakhin

$x=\sin (x+y)$
$\frac{d}{dx}x=\frac{d}{dx}\sin (x+y)$
$1=\cos (x+y)(1+\frac{dy}{dx})$ by chain rule
Therefore $\frac{dy}{dx}=\frac{1}{\cos (x+y)}-1$

**Posted:** Sat Sep 17, 2005 9:37 am

_________________
$\int\int_\Omega\,dA=\int\int_\Sigma \sqrt{E(u,v)G(u,v)-F(u,v)^{2}}\,du\,dv$
$P_{G}(\sigma_{1}, \sigma_{2}, \cdots, \sigma_{n})=\frac{1}{|G|}\sum_{\tau\in G}ind(\tau)$

DJIntel

Awesome, thanks a lot, you guys rock! What Calculus are you taking or have taken because I'm in Calc 1, and just on differentiation.

**Posted:** Sat Sep 17, 2005 12:04 pm

leepakhin

I learn calculus mostly by self-study.

**Posted:** Sun Sep 18, 2005 9:19 am

_________________
$\int\int_\Omega\,dA=\int\int_\Sigma \sqrt{E(u,v)G(u,v)-F(u,v)^{2}}\,du\,dv$
$P_{G}(\sigma_{1}, \sigma_{2}, \cdots, \sigma_{n})=\frac{1}{|G|}\sum_{\tau\in G}ind(\tau)$