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Post Posted: Jan 15, 2006, 10:10 am • # 1 


Some properties of the circumscribed quadrilateral.
Let ABCD be a quadrilateral which is circumscribed about the circle w=C(I,r).
Denote: a=AB, b=BC, c=CD, d=DA, e=AC, f=BD;
the middlepoints M, N of the diagonals AC, BD respectively;
E\in AC\cap BD, F\in AB\cap CD, G\in AD\cap BC;
the tangent - points X\in AB, Y\in BC, Z\in CD, T\in DA of the incircle w;
U\in XT\cap YZ, V\in XY\cap ZT; the area S=[ABCD], 2p=a+b+c+d. Then:

1. The quadrilateral ABCD is circumscribed \Longleftrightarrow a+c=b+d (Pithot).
2.\ E\in XZ\cap YT (Newton); I\in MN (Newton's line).
3.\ U\in BD and (D,E,B,U) is a harmonic division.
V\in AC and (A,E,C,V) is a harmonic division.
4. The quadrilateral IEUV is orthocentric, i.e. UI\perp EV and VI\perp EU.

5. If the quadrilateral ABCD is circumscribed and inscribed in the circle e=C(O,R), then:
5.1.\ ef=2r\left(r+\sqrt{4R^{2}+r^{2}}\right), OI^{2}=R^{2}+r^{2}-r\sqrt{4R^{2}+r^{2}} (Durrande).
5.2\ E\in XZ\cap YT (Newton); \frac{IM}{IN}=\frac{e}{f}; \frac{1}{e}+\frac{1}{f}=\frac{p}{4Rr}.
5.3. The power of the point E w.r.t the circle e is p_{e}(E)=\left(\frac{ef}{4R}\right)^{2};
5.4. The power of the incenter I w.r.t. the circumcircle e is p_{e}(I)=\frac{8R^{2}r^{2}}{ef}.

Remark. Maybe now the following problem seems more easily:
See www.artofproblemsolving.com/Forum/viewtopic.php?t=69101
 
 
Post Posted: Jun 15, 2007, 4:32 pm • # 2 


These properties are very interesting. I attached a diagram.


Attachments:
Circumscribed Quadrilateral Properties.pdf [5.94 KiB]
Downloaded 396 times

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-Alex
Altheman's Problem Column
 
 
Post Posted: Jul 03, 2007, 8:52 am • # 3 


(Altheman, what kind of software do you use to do this pdf's? :wink: )
 
 
Post Posted: Jul 06, 2007, 9:05 am • # 4 


Why don't we see quadrilateral in triangle language, we consider quadrilateral is as a triangle ABC with an arbitrary point M now circumscribed quadrilateral we can see as ABC and M such that MB+b=MC+c or especialy MA+a=MB+b=MC+c now I think all problems of circumscribed quadrilateral can be translated to language of geometry of triangle :).

_________________
Sum of three angles of a triangle is 180 degree in the earth and I would like to know what is sum of three angles of a triangle in a black hole ? Could andbody help me, please ? :P
 
 
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