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1969 Canadian MO Problems/Problem 10

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Problem

Let be the right-angled isosceles triangle whose equal sides have length 1. is a point on the hypotenuse, and the feet of the perpendiculars from to the other sides are and . Consider the areas of the triangles and , and the area of the rectangle . Prove that regardless of how is chosen, the largest of these three areas is at least .

Solution

Let Because triangles and both contain a right angle and a angle, they are isosceles right triangles. Hence, and

Now let's consider when or else one of triangles and will automatically have area greater than In this case, [QCRP]>[ABC]-[APQ]-[PBR]>\frac29. Therefore, one of these three figures will always have area greater than regardless of where is chosen.

1969 Canadian MO (Problems)
Preceded by
Problem 9
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