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1986 AJHSME Problems/Problem 20

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Problem

The value of the expression \frac{(304)^5}{(29.7)(399)^4} is closest to

\text{(A)}\ .003 \qquad \text{(B)}\ .03 \qquad \text{(C)}\ .3 \qquad \text{(D)}\ 3 \qquad \text{(E)}\ 30

Solution

\frac{(304)^5}{(29.7)(399)^4} \approx \frac{300^5}{30\cdot400^4} = \frac{3^5 \cdot 10^{10}}{3\cdot 4^4 \cdot 10^9} = \frac{3^... which is obviously closest to 3\rightarrow\boxed{\text{D}}.

(The original expression is approximately equal to 3.44921198.)

See Also

1986 AJHSME (Problems • Resources)
Preceded by
Problem 19 		Followed by
Problem 21
1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 • 16 • 17 • 18 • 19 • 20 • 21 • 22 • 23 • 24 • 25
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