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1986 AJHSME Problems/Problem 6

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Problem

\frac{2}{1-\frac{2}{3}}=

\text{(A)}\ -3 \qquad \text{(B)}\ -\frac{4}{3} \qquad \text{(C)}\ \frac{2}{3} \qquad \text{(D)}\ 2 \qquad \text{(E)}\ 6

Solution

Just simplify the bottom as \frac{3}{3}-\frac{2}{3}=\frac{1}{3}, getting us \frac{2}{\frac{1}{3}}, with which we multiply top and bottom by 3, we get \frac{6}{1}, or 6

\boxed{\text{E}}

See Also

1986 AJHSME (ProblemsResources)
Preceded by
Problem 5
Followed by
Problem 7
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