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1987 AJHSME Problems/Problem 10

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Problem

$4(299)+3(299)+2(299)+298=$

$\text{(A)}\ 2889 \qquad \text{(B)}\ 2989 \qquad \text{(C)}\ 2991 \qquad \text{(D)}\ 2999 \qquad \text{(E)}\ 3009$

Solution

We can make use of the distributive property as follows: $\begin{align*}4(299)+3(299)+2(299)+298 &= 4(299)+3(299)+2(299)+1(299)-1 \\&= (4+3+2+1)(299)-1 \\&= 10(299)-1 \\&a...$

$\boxed{\text{B}}$

See Also

1987 AJHSME (Problems • Resources)
Preceded by Problem 9	Followed by Problem 11
1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 • 16 • 17 • 18 • 19 • 20 • 21 • 22 • 23 • 24 • 25

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Category: Introductory Algebra Problems

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