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1987 AJHSME Problems/Problem 2

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Problem

\frac{2}{25}=

\text{(A)}\ .008 \qquad \text{(B)}\ .08 \qquad \text{(C)}\ .8 \qquad \text{(D)}\ 1.25 \qquad \text{(E)}\ 12.5

Solution

\frac{2}{25}=\frac{2\cdot 4}{25\cdot 4} = \frac{8}{100} = 0.08\rightarrow \boxed{\text{B}}

See Also

1987 AJHSME (ProblemsResources)
Preceded by
Problem 1
Followed by
Problem 3
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