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1989 AJHSME Problems/Problem 13

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Problem

\frac{9}{7\times 53} =

\text{(A)}\ \frac{.9}{.7\times 53} \qquad \text{(B)}\ \frac{.9}{.7\times .53} \qquad \text{(C)}\ \frac{.9}{.7\times 5.3} \qqu...

Solution

\begin{align*}\frac{9}{7\times 53} &= \frac{.9\times 10}{.7\times 10\times 53} \\&= \frac{.9}{.7\times 53} \rightarro...

See Also

1989 AJHSME (ProblemsResources)
Preceded by
Problem 12
Followed by
Problem 14
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