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1989 AJHSME Problems/Problem 18

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Problem

Many calculators have a reciprocal key \boxed{\frac{1}{x}} that replaces the current number displayed with its reciprocal. For example, if the display is \boxed{00004} and the \boxed{\frac{1}{x}} key is depressed, then the display becomes \boxed{000.25}. If \boxed{00032} is currently displayed, what is the fewest number of times you must depress the \boxed{\frac{1}{x}} key so the display again reads \boxed{00032}?

\text{(A)}\ 1 \qquad \text{(B)}\ 2 \qquad \text{(C)}\ 3 \qquad \text{(D)}\ 4 \qquad \text{(E)}\ 5

Solution

Let f(x)=\frac{1}{x}. We have f(f(x))=\frac{1}{\frac{1}{x}}=x Thus, we need to iterate the key pressing twice to get the display back to the original \rightarrow \boxed{\text{B}}.

See Also

1989 AJHSME (ProblemsResources)
Preceded by
Problem 17
Followed by
Problem 19
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