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1989 AJHSME Problems/Problem 20

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Problem

The figure may be folded along the lines shown to form a number cube. Three number faces come together at each corner of the cube. What is the largest sum of three numbers whose faces come together at a corner?

draw((0,0)--(0,1)--(1,1)--(1,2)--(2,2)--(2,1)--(4,1)--(4,0)--(2,0)--(2,-1)--(1,-1)--(1,0)--cycle);draw((1,0)--(1,1)--(2,1)--(...

\text{(A)}\ 11 \qquad \text{(B)}\ 12 \qquad \text{(C)}\ 13 \qquad \text{(D)}\ 14 \qquad \text{(E)}\ 15

Solution

It is clear that 6, 5, and 4 will not come together to get a sum of 15.

The faces 6, 5, and 3 come together at a common vertex, making the maximal sum 6+5+3=14\rightarrow \boxed{\text{D}}.

See Also

1989 AJHSME (ProblemsResources)
Preceded by
Problem 19
Followed by
Problem 21
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