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1989 AJHSME Problems/Problem 4

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Problem

Estimate to determine which of the following numbers is closest to \frac{401}{.205}.

\text{(A)}\ .2 \qquad \text{(B)}\ 2 \qquad \text{(C)}\ 20 \qquad \text{(D)}\ 200 \qquad \text{(E)}\ 2000

Solution

401 is around 400 and .205 is around $.2 so the fraction is approximately \frac{400}{.2}=2000\rightarrow \boxed{\text{E}}

See Also

1989 AJHSME (Problems • Resources)
Preceded by
Problem 3 		Followed by
Problem 5
1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 • 16 • 17 • 18 • 19 • 20 • 21 • 22 • 23 • 24 • 25
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