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1990 AIME Problems/Problem 3

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Problem

Let P_1^{} be a regular r~\mbox{gon} and P_2^{} be a regular s~\mbox{gon} (r\geq s\geq 3) such that each interior angle of P_1^{} is \frac{59}{58} as large as each interior angle of P_2^{}. What's the largest possible value of s_{}^{}?

Solution

The formula for the interior angle of a regular sided polygon is \frac{(n-2)180}{n}.

Thus, \frac{\frac{(r-2)180}{r}}{\frac{(s-2)180}{s}} = \frac{59}{58}. Cross multiplying and simplifying, we get \frac{58(r-2)}{r} = \frac{59(s-2)}{s}. Cross multiply and combine like terms again to yield 58rs - 58 \cdot 2s = 59rs - 59 \cdot 2r \Longrightarrow 118r - 116s = rs. Solving for r, we get r = \frac{116s}{118 - s}.

r \ge 0 and s \ge 0, making the numerator of the fraction positive. To make the denominator positive, s \le 118; the largest possible value of s is 117.

See also

1990 AIME (ProblemsResources)
Preceded by
Problem 2
Followed by
Problem 4
1 2 3 4 5 6 7 8 9 10 11 12 13 14 15
Looking for a challenging geometry text? Preparing for MATHCOUNTS or the AMC exams? Check out Art of Problem Solving's Introduction to Geometry by Richard Rusczyk.
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