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1991 AJHSME Problems/Problem 10

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Problem 10

The area in square units of the region enclosed by parallelogram ABCD is

unitsize(24);pair A,B,C,D;A=(-1,0); B=(0,2); C=(4,2); D=(3,0); draw(A--B--C--D); draw((0,-1)--(0,3)); draw((-2,0)--(6,0));dra...

\text{(A)}\ 6 \qquad \text{(B)}\ 8 \qquad \text{(C)}\ 12 \qquad \text{(D)}\ 15 \qquad \text{(E)}\ 18

Solution

The base is \overline{BC}=4. The height has a length of the difference of the y-coordinates of A and B, which is 2. Therefore the area is 4\cdot 2=8\Rightarrow \boxed{\mathrm{B}}.

See Also

1991 AJHSME (Problems • Resources)
Preceded by
Problem 9 		Followed by
Problem 11
1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 • 16 • 17 • 18 • 19 • 20 • 21 • 22 • 23 • 24 • 25
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