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1991 AJHSME Problems/Problem 14

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Problem

Several students are competing in a series of three races. A student earns 5 points for winning a race, 3 points for finishing second and 1 point for finishing third. There are no ties. What is the smallest number of points that a student must earn in the three races to be guaranteed of earning more points than any other student?

\text{(A)}\ 9 \qquad \text{(B)}\ 10 \qquad \text{(C)}\ 11 \qquad \text{(D)}\ 13 \qquad \text{(E)}\ 15

Solution

There are two ways for a student to get 11: 5+5+1 and 5+3+3. Clearly if someone gets one of these combinations someone else could get the other, so we are not guaranteed the most points with 11.

There is only one way to get 13 points: 5+5+3. In this case, the largest score another person could get is 5+3+3=11, so having 13 points guarantees having more points than any other person \rightarrow \boxed{\text{D}}.

See Also

1991 AJHSME (ProblemsResources)
Preceded by
Problem 13
Followed by
Problem 15
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Want to learn how to tackle those tough MATHCOUNTS and AMC counting and probability problems? Check out Art of Problem Solving's Introduction to Counting & Probability by David Patrick.
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