1995 AHSME Problems/Problem 4
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Problem
If 
is 
of 
, is 
of 
, and 
is 
of , then 
Solution
We are given: 
, 
, 
. We want M in terms of N, so we substitute N into everything:
See also
| 1995 AHSME (Problems) | ||
| Preceded by Problem 3 | Followed by Problem 5 | |
| 1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 • 16 • 17 • 18 • 19 • 20 • 21 • 22 • 23 • 24 • 25 • 26 • 27 • 28 • 29 • 30 | ||
