1995 AHSME Problems/Problem 9

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Problem

Consider the figure consisting of a square, its diagonals, and the segments joining the midpoints of opposite sides. The total number of triangles of any size in the figure is

$\mathrm{(A) \ 10 } \qquad \mathrm{(B) \ 12 } \qquad \mathrm{(C) \ 14 } \qquad \mathrm{(D) \ 16 } \qquad \mathrm{(E) \ 18 }$

Solution

[Asy_image]

There are 8 little triangles, 4 triangles with twice the area, and 4 triangles with four times the area of the smaller triangles. $8+4+4=16\Rightarrow \mathrm{(D)}$

1995 AHSME (Problems)
Preceded by Problem 8	Followed by Problem 10
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1995 AHSME Problems/Problem 9

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Problem

Solution

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