AoPSWiki
Want to learn how to tackle those tough AMC/AIME/Olympiad algebra problems? Check out Art of Problem Solving's NEW Intermediate Algebra by Richard Rusczyk and Mathew Crawford. Over 1600 problems!
Personal tools

1995 AIME Problems/Problem 3

From AoPSWiki

Problem

Starting at an object moves in the coordinate plane via a sequence of steps, each of length one. Each step is left, right, up, or down, all four equally likely. Let be the probability that the object reaches in six or fewer steps. Given that can be written in the form where and are relatively prime positive integers, find

Solution

It takes an even number of steps for the object to reach , so the number of steps the object may have taken is either or .

If the object took steps, then it must have gone two steps N and two steps E, in some permutation. There are ways for these four steps of occuring, and the probability is .

If the object took steps, then it must have gone two steps N and two steps E, and an additional pair of moves that would cancel out, either N/S or W/E. The sequences N,N,N,E,E,S can be permuted in ways. However, if the first four steps of the sequence are N,N,E,E in some permutation, it would have already reached the point in four moves. There are ways to order those four steps and ways to determine the order of the remaining two steps, for a total of sequences that we have to exclude. This gives sequences of steps. There are the same number of sequences for the steps N,N,E,E,E,W, so the probability here is .

The total probability is \frac{6}{4^4} + \frac{96}{4^6} = \frac{3}{64}, and .

See also

1995 AIME (ProblemsResources)
Preceded by
Problem 2
Followed by
Problem 4
1 2 3 4 5 6 7 8 9 10 11 12 13 14 15
Want to learn how to tackle those tough AMC/AIME/Olympiad counting and probability problems? Check out Art of Problem Solving's NEW Intermediate Counting & Probability by David Patrick.
© Copyright 2008 AoPS Incorporated. All Rights Reserved. • FoundationPrivacyContact Us