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1997 AIME Problems/Problem 5

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Problem

The number r can be expressed as a four-place decimal 0.abcd, where a, b, c, and d represent digits, any of which could be zero. It is desired to approximate r by a fraction whose numerator is 1 or 2 and whose denominator is an integer. The closest such fraction to r is \frac 27. What is the number of possible values for r?

Solution

The nearest fractions to \frac 27 with numerator 1 are \frac 13, \frac 14; and with numerator 2 are \frac 26, \frac 28 = \frac 13, \frac 14 anyway. For \frac 27 to be the best approximation for r, the decimal must be closer to \frac 27 \approx .28571 than to \frac 13 \approx .33333 or \frac 14 \approx .25.

Thus r can range between \frac{\frac 14 + \frac{2}{7}}{2} \approx .267857 and \frac{\frac 13 + \frac{2}{7}}{2} \approx .309523. At r = .2679, .3095, it becomes closer to the other fractions, so .2679 \le r \le .3095 and the number of values of r is 3095 - 2679 + 1 = \boxed{417}.

See also

1997 AIME (ProblemsResources)
Preceded by
Problem 4
Followed by
Problem 6
1 2 3 4 5 6 7 8 9 10 11 12 13 14 15
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