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1997 PMWC Problems/Problem I12

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Problem

In a die, 1 and 6, 2 and 5, 3 and 4 appear on opposite faces. When 2 dice are thrown, product of numbers appearing on the top and bottom faces of the 2 dice are formed as follows:

  • number on top face of 1st die x number on top face of 2nd die
  • number on top face of 1st die x number on bottom face of 2nd die
  • number on bottom face of 1st die x number on top face of 2nd die
  • number on bottom face of 1st die x number on bottom face of 2nd die

What is the sum of these 4 products ?


Solution

Let be the two numbers at the top of the two dice. Then

xy + x(7-y) + (7-x)y + (7-x)(7-y) = (x + (7-x))(y + (7 - y)) = 49

See also

1997 PMWC (Problems)
Preceded by
Problem I11
Followed by
Problem I13
I: 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15
T: 1 2 3 4 5 6 7 8 9 10
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