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1997 PMWC Problems/Problem I8

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Problem

997-996-995+994+993-992+991-990-989+988+989-986+\cdots+7-6-5+4+3-2+1=?

Solution

Wee look for a pattern:

+--++-+--++-+

So the pattern is +--++-. We find the value of one round:

(n-(n-1)-(n-2)+(n-3)+(n-4)-(n-5))=1

So we just need to find the number of rounds.

There are 6 terms per round, and the +1 doesn't belong to a round, so 996/6=166


See Also

1997 PMWC (Problems)
Preceded by
Problem I7
Followed by
Problem I9
I: 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15
T: 1 2 3 4 5 6 7 8 9 10
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