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1998 AHSME Problems/Problem 24

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Problem

Call a 7-digit telephone number d_1d_2d_3-d_4d_5d_6d_7 memorable if the prefix sequence d_1d_2d_3 is exactly the same as either of the sequences d_4d_5d_6 or d_5d_6d_7 (possibly both). Assuming that each d_i can be any of the ten decimal digits 0,1,2, \ldots, 9, the number of different memorable telephone numbers is

\mathrm{(A)}\ 19,810\qquad\mathrm{(B)}\ 19,910\qquad\mathrm{(C)}\ 19,990\qquad\mathrm{(D)}\ 20,000\qquad\mathrm{(E)}\ 20,100

Solution

Let A represent the set of telephone numbers with \overline{d_1d_2d_3} = \overline{d_4d_5d_6} (of which there are 1000 possibilities for \overline{d_1d_2d_3} and 10 for d_7), and B those such that \overline{d_1d_2d_3} = \overline{d_5d_6d_7}. Then A \cap B (the telephone numbers that belong to both A and B) is the set of telephone numbers such that d_1 = d_2 = d_3 = d_4 = d_5 = d_6 = d_7, of which there are 10 possibilities. By the Principle of Inclusion-Exclusion,

|A \cup B| = |A| + |B| - |A \cap B| = 1000 \times 10 + 1000 \times 10 - 10 = 19990 \Rightarrow \mathrm{(C)}

See also

1998 AHSME (Problems)
Preceded by
Problem 23
Followed by
Problem 25
1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30
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