1999 AHSME Problems/Problem 1
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Contents |
Problem
Solution
Solution 1
If we group consecutive terms together, we get 
, and since there are 49 pairs of terms the answer is 
.
Solution 2
Let 
.
Therefore, 
We add:
See also
| 1999 AHSME (Problems) | ||
| Preceded by First question | Followed by Problem 2 | |
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