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2000 AMC 10 Problems/Problem 2

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Problem

$2000\left(2000^{2000}\right)=$

$\mathrm{(A)}\ {2000}^{2001} \qquad \mathrm{(B)}\ {4000}^{2000} \qquad \mathrm{(C)}\ {2000}^{4000} \qquad \mathrm{(D)}\ {4,000...$

Solution

$2000 \cdot 2000^{2000}=2000^1 \cdot 2000^{2000}=2000^{2000+1}=2000^{2001}$ .

$\boxed{\text{A}}$

See Also

2000 AMC 10 (Problems • Resources)
Preceded by Problem 1	Followed by Problem 3
1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 • 16 • 17 • 18 • 19 • 20 • 21 • 22 • 23 • 24 • 25

Retrieved from "http://www.artofproblemsolving.com/Wiki/index.php/2000_AMC_10_Problems/Problem_2"

Want to learn how to tackle those tough AMC/AIME/Olympiad algebra problems? Check out Art of Problem Solving's Intermediate Algebra by Richard Rusczyk and Mathew Crawford. Over 1600 problems!

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