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2000 AMC 12 Problems/Problem 15

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Problem

Let f be a function for which f(x/3) = x^2 + x + 1. Find the sum of all values of z for which f(3z) = 7.

\text {(A)}\ -1/3 \qquad \text {(B)}\ -1/9 \qquad \text {(C)}\ 0 \qquad \text {(D)}\ 5/9 \qquad \text {(E)}\ 5/3

Solution

Let y = \frac{x}{3}; then f(y) = (3y)^2 + 3y + 1 = 9y^2 + 3y+1. Thus f(3z)-7=81z^2+9z-6=3(9z-2)(3z+1)=0, and z = \frac{-1}{3}, \frac{2}{9}. These sum up to \frac{-1}{9}\ \mathrm{(B)}.

Alternative solution: When we have 0=81z^2+9z-6, we just use Vieta's and get the sum is \frac{-9}{81}=\frac{-1}{9}

See also

2000 AMC 12 (ProblemsResources)
Preceded by
Problem 14
Followed by
Problem 16
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