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2001 AMC 12 Problems/Problem 13

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Problem

The parabola with equation p(x) = ax^2+bx+c and vertex (h,k) is reflected about the line y=k. This results in the parabola with equation q(x) = dx^2+ex+f. Which of the following equals a+b+c+d+e+f?

(\mathrm{A})\ 2b \qquad (\mathrm{B})\ 2c \qquad (\mathrm{C})\ 2a+2b \qquad (\mathrm{D})\ 2h \qquad (\mathrm{E})\ 2k

Solution

We write p(x) as a(x-h)^2+k (this is possible for any parabola). Then the reflection of p(x) is q(x) = -a(x-h)^2+k. Then we find p(x) + q(x) = 2k. Since p(1) = a+b+c and q(1) = d+e+f, we have a+b+c+d+e+f = 2k, so the answer is \mathrm{E}.

See Also

2001 AMC 12 (ProblemsResources)
Preceded by
Problem 12
Followed by
Problem 14
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