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2001 AMC 12 Problems/Problem 20

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Problem

Points A = (3,9), B = (1,1), C = (5,3), and D=(a,b) lie in the first quadrant and are the vertices of quadrilateral ABCD. The quadrilateral formed by joining the midpoints of \overline{AB}, \overline{BC}, \overline{CD}, and \overline{DA} is a square. What is the sum of the coordinates of point D?

\text{(A) }7\qquad\text{(B) }9\qquad\text{(C) }10\qquad\text{(D) }12\qquad\text{(E) }16

Solution

We already know two vertices of the square: (A+B)/2 = (2,5) and (B+C)/2 = (3,2).

There are only two possibilities for the other vertices of the square: either they are (6,3) and (5,6), or they are (0,1) and (-1,4). The second case would give us D outside the first quadrant, hence the first case is the correct one. As (6,3) is the midpoint of CD, we can compute D=(7,3), and 7+3=\boxed{10}.

See Also

2001 AMC 12 (ProblemsResources)
Preceded by
Problem 19
Followed by
Problem 21
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