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2002 AMC 10A Problems/Problem 20

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Problem

Points A,B,C,D,E and F lie, in that order, on \overline{AF}, dividing it into five segments, each of length 1. Point G is not on line AF. Point H lies on \overline{GD}, and point J lies on \overline{GF}. The line segments \overline{HC}, \overline{JE}, and \overline{AG} are parallel. Find HC/JE.

\text{(A)}\ 5/4 \qquad \text{(B)}\ 4/3 \qquad \text{(C)}\ 3/2 \qquad \text{(D)}\ 5/3 \qquad \text{(E)}\ 2

Solution

As \overline{JE} is parallel to \overline{AG}, angles FHD and FGA are congruent. Also, angle F is clearly congruent to itself. From SSS similarity, \triangle AGF \sim \triangle EJF; hence \frac {AG}{JE} =5. Similarly, \frac {AG}{HC} = 3. Thus, \frac {HC}{JE} = \boxed{\frac {5}{3}\Rightarrow \text{(D)}}.

See Also

2002 AMC 10A (ProblemsResources)
Preceded by
Problem 19
Followed by
Problem 21
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