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2002 AMC 10B Problems/Problem 14

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Problem

The number 25^{64}\cdot 64^{25} is the square of a positive integer N. In decimal representation, the sum of the digits of N is

\mathrm{(A) \ } 7\qquad \mathrm{(B) \ } 14\qquad \mathrm{(C) \ } 21\qquad \mathrm{(D) \ } 28\qquad \mathrm{(E) \ } 35

Solution

Taking the squareroot, N=5^{64}\cdot 8^{25}=5^{64}\cdot 2^{75}=10^{64}\cdot 2^{11}. This is 2048 with a lot of 0's on the end. So, the sum of the digits of N is 14\Longrightarrow\mathrm{ (B) \ }

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