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2002 AMC 10B Problems/Problem 15

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Problem

The positive integers A, B, A-B, and A+B are all prime numbers. The sum of these four primes is


\mathrm{(A) \ } \text{even}\qquad \mathrm{(B) \ } \text{divisible by }3\qquad \mathrm{(C) \ } \text{divisible by }5\qquad \ma...

Solution

The sum is A+B+A-B+A+B=3A+B. Since A, A-B, and A+B are all prime, they must all be odd, so B=2. A quick check gives A=5. Hence, the sum is 17, which is prime. \mathrm{ (E) \ }

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