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2002 AMC 12A Problems/Problem 17

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Problem

Several sets of prime numbers, such as \{7,83,421,659\} use each of the nine nonzero digits exactly once. What is the smallest possible sum such a set of primes could have?

\text{(A) }193\qquad\text{(B) }207\qquad\text{(C) }225\qquad\text{(D) }252\qquad\text{(E) }447

Solution

Neither of the digits 4, 6, and 8 can be a units digit of a prime. Therefore the sum of the set is at least 40 + 60 + 80 + 1 + 2 + 3 + 5 + 7 + 9 = 207.

We can indeed create a set of primes with this sum, for example the following set works: \{ 41, 67, 89, 2, 3, 5 \}.

Thus the answer is \boxed{207}.

See Also

2002 AMC 12A (ProblemsResources)
Preceded by
Problem 16
Followed by
Problem 18
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