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2002 AMC 12A Problems/Problem 4

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Problem

Find the degree measure of an angle whose complement is 25% of its supplement.

\mathrm{(A) \ 48 } \qquad \mathrm{(B) \ 60 } \qquad \mathrm{(C) \ 75 } \qquad \mathrm{(D) \ 120 } \qquad \mathrm{(E) \ 150 }


Solution

4(90-x)=(180-x)

360-4x=180-x

3x=180

x=60 \Rightarrow \mathrm {(B)}

See Also

2002 AMC 12A (Problems • Resources)
Preceded by
Problem 3 		Followed by
Problem 5
1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 • 16 • 17 • 18 • 19 • 20 • 21 • 22 • 23 • 24 • 25
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