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2002 AMC 12B Problems/Problem 3

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Problem

For how many positive integers n is n^2 - 3n + 2 a prime number?

\mathrm{(A)}\ \text{none}\qquad\mathrm{(B)}\ \text{one}\qquad\mathrm{(C)}\ \text{two}\qquad\mathrm{(D)}\ \text{more\ than\ tw...

Solution

n^2 - 3n + 2 = (n-2)(n-1), which is the product of two integers greater than 1 if n \ge 4. When n = 1,2, the expression evaluates to 0; when n = 3 it evaluates to be 2, a prime number. The answer is 1\ \mathrm{(B)}.

See also

2002 AMC 12B (ProblemsResources)
Preceded by
Problem 2
Followed by
Problem 4
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