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2003 AIME II Problems/Problem 13

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Problem

A bug starts at a vertex of an equilateral triangle. On each move, it randomly selects one of the two vertices where it is not currently located, and crawls along a side of the triangle to that vertex. Given that the probability that the bug moves to its starting vertex on its tenth move is m/n, where m and n are relatively prime positive integers, find m + n.

Solution

Solution 1

After n moves, there are 2^n possible paths for the ant. But the key is to realize that the number of paths that get back the the start after n moves is the same as the number of paths the do NOT get the ant to the start after n-1 moves. So after 1 move, there are 0 ways the get to the start. After 2 moves, there are 2^1-0 ways to get to the start. After 3 moves, there are 2^2-(2^1-0) ways to get to the start. Thus after 10 moves, there are 2^9-(2^8-(2^7-(2^6-(2^5-(2^4-(2^3-(2^2-2)))))))= 342 ways to get to the start, so the probability is 342/1024=171/512 and the answer is 683.

Solution 2

Consider there to be a clockwise and a counterclockwise direction around the triangle. Then, in order for the ant to return to the original vertex, the net number of clockwise steps must be a multiple of 3, i.e., \#CW - \#CCW \equiv 0 \pmod{3}. Since \#CW + \#CCW = 10, it is only possible that (\#CW,\, \#CCW) = (5,5), (8,2), (2,8).

In the first case, we pick 5 out of the ant's 10 steps to be clockwise, for a total of {10 \choose 5} paths. In the second case, we choose 8 of the steps to be clockwise, and in the third case we choose 2 to be clockwise. Hence the total number of ways to return to the original vertex is {10 \choose 5} + {10 \choose 8} + {10 \choose 2} = 252 + 45 + 45 = 342. Since the ant has two possible steps at each point, there are 2^{10} routes the ant can take, and the probability we seek is \frac{342}{2^{10}} = \frac{171}{512}, and the answer is 683.

See also

2003 AIME II (ProblemsResources)
Preceded by
Problem 12
Followed by
Problem 14
1 2 3 4 5 6 7 8 9 10 11 12 13 14 15
Looking for a challenging geometry text? Preparing for MATHCOUNTS or the AMC exams? Check out Art of Problem Solving's Introduction to Geometry by Richard Rusczyk.
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