AoPSWiki
Want to learn how to tackle those tough AMC/AIME/Olympiad algebra problems? Check out Art of Problem Solving's Intermediate Algebra by Richard Rusczyk and Mathew Crawford. Over 1600 problems!

2003 AIME I Problems/Problem 5

From AoPSWiki

Problem

Consider the set of points that are inside or within one unit of a rectangular parallelepiped (box) that measures 3 by 4 by 5 units. Given that the volume of this set is \frac{m + n\pi}{p}, where m, n, and p are positive integers, and n and p are relatively prime, find m + n + p.

Solution

size(220);import three; currentprojection = perspective(5,4,3); defaultpen(linetype("8 8")+linewidth(0.6));draw(box...

The set can be broken into several parts: the big 3\times 4 \times 5 parallelepiped, 6 external parallelepipeds that each share a face with the large parallelepiped and have a height of 1, the 1/8 spheres (one centered at each vertex of the large parallelepiped), and the 1/4 cylinders connecting each adjacent pair of spheres.

  • The volume of the parallelepiped is 3 \times 4 \times 5 = 60 cubic units.
  • The volume of the external parallelepipeds is 2(3 \times 4 \times 1)+2(3 \times 5 \times 1 )+2(4 \times 5 \times 1)=94.
  • There are 8 of the 1/8 spheres, each of radius 1. Together, their volume is \frac{4}{3}\pi.
  • There are 12 of the 1/4 cylinders, so 3 complete cylinders can be formed. Their volumes are 3\pi, 4\pi, and 5\pi, adding up to 12\pi.

The combined volume of these parts is 60+94+\frac{4}{3}\pi+12\pi = \frac{462+40\pi}{3}. Thus, the answer is m+n+p = 462+40+3 = \boxed{505}.

See also

2003 AIME I (ProblemsResources)
Preceded by
Problem 4
Followed by
Problem 6
1 2 3 4 5 6 7 8 9 10 11 12 13 14 15
Want to learn how to tackle those tough AMC/AIME/Olympiad counting and probability problems? Check out Art of Problem Solving's Intermediate Counting & Probability by David Patrick.
© Copyright 2008 AoPS Incorporated. All Rights Reserved. • FoundationPrivacyContact Us