AoPSWiki
Looking for a challenging algebra text? Preparing for MATHCOUNTS or the AMC exams?
Check out Art of Problem Solving's Introduction to Algebra by Richard Rusczyk.

2003 AMC 10A Problems/Problem 12

From AoPSWiki

Problem

A point (x,y) is randomly picked from inside the rectangle with vertices (0,0), (4,0), (4,1), and (0,1). What is the probability that x<y?

\mathrm{(A) \ } \frac{1}{8}\qquad \mathrm{(B) \ } \frac{1}{4}\qquad \mathrm{(C) \ } \frac{3}{8}\qquad \mathrm{(D) \ } \frac{1...

Solution

The rectangle has a width of 4 and a height of 1.

The area of this rectangle is 4\cdot1=4.

The line x=y intersects the rectangle at (0,0) and (1,1).

The area which x>y is the right isosceles triangle with side length 1 that has vertices at (0,0), (1,1), and (0,1).

The area of this triangle is \frac{1}{2}\cdot1^{2}=\frac{1}{2}

Therefore, the probability that x<y is \frac{\frac{1}{2}}{4}=\frac{1}{8} \Rightarrow A

See Also

2003 AMC 10A (ProblemsResources)
Preceded by
Problem 11
Followed by
Problem 13
1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25
Want to learn how to tackle those tough MATHCOUNTS and AMC counting and probability problems? Check out Art of Problem Solving's Introduction to Counting & Probability by David Patrick.
© Copyright 2008 AoPS Incorporated. All Rights Reserved. • FoundationPrivacyContact Us