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2003 AMC 10A Problems/Problem 8

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Problem

What is the probability that a randomly drawn positive factor of 60 is less than 7

\mathrm{(A) \ } \frac{1}{10}\qquad \mathrm{(B) \ } \frac{1}{6}\qquad \mathrm{(C) \ } \frac{1}{4}\qquad \mathrm{(D) \ } \frac{...

Solution

For a positive number n which is not a perfect square, exactly half of the positive factors will be less than \sqrt{n}.

Since 60 is not a perfect square, half of the positive factors of 60 will be less than \sqrt{60}\approx 7.746.

Clearly, there are no positive factors of 60 between 7 and \sqrt{60}.

Therefore half of the positive factors will be less than 7.

So the answer is \frac{1}{2} \Rightarrow E.

See Also

2003 AMC 10A (ProblemsResources)
Preceded by
Problem 7
Followed by
Problem 9
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