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2004 AMC 10B Problems/Problem 16

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Problem

Three circles of radius 1 are externally tangent to each other and internally tangent to a larger circle. What is the radius of the large circle?

\mathrm{(A) \ } \frac{2 + \sqrt{6}}{3} \qquad \mathrm{(B) \ } 2 \qquad \mathrm{(C) \ } \frac{2 + 3\sqrt{2}}{2} \qquad \mathrm...

Solution

The situation in shown in the picture below. The radius we seek is SD = AD + AS. Clearly AD=1. The point S is clearly the center of the equilateral triangle ABC, thus AS is 2/3 of the altitude of this triangle. We get that AS = \frac23 \cdot \sqrt 3. Therefore the radius we seek is 1 + \frac23 \cdot \sqrt 3 = \boxed{\frac{3+2\sqrt{3}}3}.

WARNING. Note that the answer does not correspond to any of the five options. Most probably there is a typo in option D.

unitsize(2cm);pair A=(0,0), B=dir(0)*2, C=dir(60)*2;draw(circle(A,1));draw(circle(B,1));draw(circle(C,1));dot(A); dot(B); dot...

See also

2004 AMC 10B (ProblemsResources)
Preceded by
Problem 15
Followed by
Problem 17
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