2004 AMC 12A Problems/Problem 3
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Problem
For how many ordered pairs of positive integers
is
?
Solution
Every integer value of
leads to an integer solution for
Since
must be positive,
Also,
Since
must be positive,
This leaves
values for y, which mean there are
solutions to the equation
See Also
| 2004 AMC 12A (Problems) | ||
| Preceded by Problem 2 | Followed by Problem 4 | |
| 1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 • 16 • 17 • 18 • 19 • 20 • 21 • 22 • 23 • 24 • 25 | ||





